b^2-10b+25=-121

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Solution for b^2-10b+25=-121 equation:


Simplifying
b2 + -10b + 25 = -121

Reorder the terms:
25 + -10b + b2 = -121

Solving
25 + -10b + b2 = -121

Solving for variable 'b'.

Reorder the terms:
25 + 121 + -10b + b2 = -121 + 121

Combine like terms: 25 + 121 = 146
146 + -10b + b2 = -121 + 121

Combine like terms: -121 + 121 = 0
146 + -10b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-146' to each side of the equation.
146 + -10b + -146 + b2 = 0 + -146

Reorder the terms:
146 + -146 + -10b + b2 = 0 + -146

Combine like terms: 146 + -146 = 0
0 + -10b + b2 = 0 + -146
-10b + b2 = 0 + -146

Combine like terms: 0 + -146 = -146
-10b + b2 = -146

The b term is -10b.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10b + 25 + b2 = -146 + 25

Reorder the terms:
25 + -10b + b2 = -146 + 25

Combine like terms: -146 + 25 = -121
25 + -10b + b2 = -121

Factor a perfect square on the left side:
(b + -5)(b + -5) = -121

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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